Summary The three-member bench of the Supreme Court will announce verdict at 9:00AM.
ISLAMABAD (Dunya News) – Supreme Court (SC) of Pakistan will announce verdict in contempt case against Pakistan Muslim League Nawaz’s (PML-N) leader and former federal minister for privatization Daniyal Aziz today (Thursday).
The three-member bench of the Supreme Court will announce verdict at 9:00AM.
The PML-N’s stalwart was served with contempt notice on Feb-2 over his controversial speeches against judiciary following which the apex court had issued a show-cause notice to Aziz on Feb-19 this year.
Finally, the former minister was indicted on March-13 under Article 204 of the Constitution and Contempt of Court Ordinance, 2003 whereas the verdict in high-profile case was reserved on May-3 after both sides concluded the arguments.
It is worth mentioning here that PML-N’s top brass has awarded party ticket to Aziz to contest general elections 2018 from Narowal’s NA-77.
The case was initiated against the minister on February 2 over his alleged anti-judiciary speeches and remarks made during television shows.
The SC bench had stated — in prima facie — Danyial Aziz has been found guilty of contempt of court as per TV recordings and newspapers’ clippings dated 9th of June-2017, 15th and 31st of Dec-2017.
However, Aziz had blamed media for misrepresentation of his statements and out of context reporting.
Aziz claimed that he has always respected the courts and talked within the limits of ethical codes on sub judice cases. He said he tried neither to dishonour the constitutional institutes nor become an obstacle in the judicial process and justice.
